获取员工其当前的薪水比其manager当前薪水还高的相关信息

CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY ( `emp_no` , `dept_no` ));
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY ( `emp_no` , `dept_no` ));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY ( `emp_no` , `from_date` ));

select t1.emp_no,t2.manager_no,t1.salary emp_salary,t2.manager_salary from (select de.emp_no,salary from dept_emp de,salaries s where de.emp_no not in (select dept_manager.emp_no from dept_manager) and de.emp_no = s.emp_no and s.to_date = '9999-01-01') t1,(select dm.emp_no manager_no,salary manager_salary,dept_no from dept_manager dm,salaries s where dm.emp_no = s.emp_no and s.to_date = '9999-01-01') t2,dept_emp de where t1.emp_no = de.emp_no and de.dept_no = t2.dept_no and t1.salary > manager_salary

select dm.emp_no manager_no,salary manager_salary,dept_no from dept_manager dm,salaries s where dm.emp_no = s.emp_no and s.to_date = '9999-01-01'

select de.emp_no,salary from dept_emp de,salaries s where de.emp_no not in (select dept_manager.emp_no from dept_manager) and de.emp_no = s.emp_no and s.to_date = '9999-01-01'