Fetch the repository succeeded.
a = input().split()
a1 = []
for k in a:
# a1.append(k)#str
a1.append(int(k))#int,得到list,推荐用下面那个一句话的
或
line = list(map(int,input().split(' '))) #直接得到list
或
n = int(input())#输入只是一个数字
'多行输入'
res = []
n = int(input())#行数
for _ in range(n):
s = input()
if s!='':
temp = [j for j in s.split()] #str输入
# temp = [int(j) for j in s.split()] #int输入
res.append(temp[0])
else:
break
print(res)
ef F(data):
return data
'多行输入'
res = []
n = int(input())#行数
for _ in range(n):
s = input()
if s!='':
temp = [j for j in s.split()] #str输入
# temp = [int(j) for j in s.split()] #int输入
res.append(temp[0])
else:
break
for i in res:
print(F(i)) #每行只输出一个
# print(F(i), end=' ') #全在同一行内输出,用空格隔开
def F(data):
return data
'多行输入'
res = []
n = int(input())#行数
for _ in range(n):
s = input()
if s!='':
temp = [j for j in s.split()] #str输入
# temp = [int(j) for j in s.split()] #int输入
res.append(temp[0])
else:
break
for i in res:
# print(F(i)) #每行只输出一个
print(F(i), end=' ') #全在同一行内输出,用空格隔开
'多行输入,行数未知'
res = []
while True:
try:
s = input()
# res.append(list(map(int, s.split(' '))))
res.append(list(map(str, s.split(' '))))
except:
break
往下n行数据对应n,再m行数据对应m
info = list(map(int,input().split(' ')))
a = []
b = []
for i in range(info[0]):
a.append(input().split(' '))
for j in range(info[1]):
b.append(input().split(' '))
print(a)
print(b)
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